Wonder if anyone will go 0/19 in the ballot… 11:08 - Sep 6 with 1466 views | Matt_Netherlands | Seen a few people be 0/3. If there’s 10k members and roughly 1,250 ballot tickets per game then it’s about a 1/8 chance. So on average people will end up with two wins per season, assuming every member enters for every game - which they won’t. Wonder if the club have rules / algorithms in place where people can’t win two games in a Row or if unsuccessful people get a better chance the next time around etc? Similarly, there will be some lucky and smug people who probably walk away with 7/8 ballot wins. 1,250 calculation as follows…. 30,000 capacity - 21,000 ST - 3,000 away - 1,000 comps, hospitality etc Leaves 5,000 tickets Clubs have said 25% of remaining capacity goes to ballot. |  | | |  |
Wonder if anyone will go 0/19 in the ballot… on 12:42 - Sep 6 with 1316 views | Freddies_Ears | I make it that, after 8 ballots, you have a equal chance of having "won" more or less than 1 ticket. Likelihood after 19 ballots of having zero "wins" is very low, but not zero. Some will have managed several "wins", and an ever-decreasing number zero. |  | |  |
Wonder if anyone will go 0/19 in the ballot… on 13:20 - Sep 6 with 1206 views | BlueJudge |
Wonder if anyone will go 0/19 in the ballot… on 12:42 - Sep 6 by Freddies_Ears | I make it that, after 8 ballots, you have a equal chance of having "won" more or less than 1 ticket. Likelihood after 19 ballots of having zero "wins" is very low, but not zero. Some will have managed several "wins", and an ever-decreasing number zero. |
Also add in the reduction if you are entering the ballot with ‘Friends & Family’. That would reduce the probability massively. |  | |  |
Wonder if anyone will go 0/19 in the ballot… on 14:06 - Sep 6 with 1113 views | Vaughan8 | I don't know if anything has been published about how it works in detail but do they have some sort of algorithm that if you get a ticket, you have less chance of getting one in the next few, or is it a straight ballot every time? |  | |  |
Wonder if anyone will go 0/19 in the ballot… on 14:31 - Sep 6 with 1025 views | tommcd | If I can remember GCSE probability (good chance I've got this wrong!): Assuming a 1/8 chance of success (meaning a 7/8 chance of loss), over the course of a season, with average luck you would expect: Probability of a win in the ballot sometime in the season (assuming an unweighted ballot everytime): Win in match1 OR win in match2 OR win in match3 OR win in match4 OR ... Which is: (1/8) + (1/8) + (1/8) + (1/8) + ... Equivalent to (1/8) * 19 = 2.38 = 238% Hence you would 'expect' at least 2 ballot wins throughout the season. But there is a statistical chance you might go the whole season without a win. The probability of going the whole season without a ballot win is (assuming an unweighted ballot everytime): Lose in match1 AND lose in match2 AND lose in match 3 AND lose in match4 AND ... Which is: (7/8) * (7/8) * (7/8) * (7/8) * ... Equivalent to (7/8)^19 = 0.079 = 7.9% [Post edited 6 Sep 2024 14:32]
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